When an object is placed 60 cms in front of a diverging lens, a virtual image is formed 20 cm from the lens.
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A point object is placed 60 cm in front of a convex lens of focal length 30 cm. A plane mirror is placed 10 cm behind the convex lens. Where is the image formed by this system?
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2 ANSWERS

Aqif Bhat, B.E from Government College of Engineering and Technology, Jammu (2020)
Answered Jul 2, 2018 · Author has 143answers and 97.6k answer views
Here U=-60cm ( distance of object from optical centre considering sign conventions also)
f=+30 cm ( positive for convex lens)
STEP1) Considering first only the image formation by lens :
We have lens formula as -1/u+1/v=1/f
-(1/-60)+1/v=1/30
1/v=1/30–1/60
1/v=1/60
V=60 cm( distance of image formed on the other side of lens)
STEP2)Image formation by mirror
U(distance of object)= 60–10 =50 cm (object is virtual here so real image will be formed by plane mirror)
V(image distance)=50 cm in front of mirror OR 40 cm from optical centre of lens on the other side of lens .
STEP3) image formation by lens again:
U=object distance =+40 cm (object is virtual )
f=+30 cm
V=?
Using lens formula again
-1/40+1/V=1/30
1/v=7/120
V=17.14cm
So finally image is formed at a distance of 17.14 cm from the optical centre of lens on the object’s side .
The distance of image from object is equal to
60–17.14=44.86 cm
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2 ANSWERS

Aqif Bhat, B.E from Government College of Engineering and Technology, Jammu (2020)
Answered Jul 2, 2018 · Author has 143answers and 97.6k answer views
Here U=-60cm ( distance of object from optical centre considering sign conventions also)
f=+30 cm ( positive for convex lens)
STEP1) Considering first only the image formation by lens :
We have lens formula as -1/u+1/v=1/f
-(1/-60)+1/v=1/30
1/v=1/30–1/60
1/v=1/60
V=60 cm( distance of image formed on the other side of lens)
STEP2)Image formation by mirror
U(distance of object)= 60–10 =50 cm (object is virtual here so real image will be formed by plane mirror)
V(image distance)=50 cm in front of mirror OR 40 cm from optical centre of lens on the other side of lens .
STEP3) image formation by lens again:
U=object distance =+40 cm (object is virtual )
f=+30 cm
V=?
Using lens formula again
-1/40+1/V=1/30
1/v=7/120
V=17.14cm
So finally image is formed at a distance of 17.14 cm from the optical centre of lens on the object’s side .
The distance of image from object is equal to
60–17.14=44.86 cm
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