Physics, asked by kiean, 6 months ago

when an object is placed anywhere between optical centre at infinity infromt of concave lens the image is formwd is (i)b/w optical centre and F (ii) virtual and erect (iii) Diminshed
draw the diagram​

Answers

Answered by Dikshant2005
0

Answer:

A diminished, virtual and erect image is formed between principal focus F1 and optical centre, O; when object is placed between optical centre and infinity of a concave lens. Properties of Image: Image is diminished, virtual and erect.

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Answered by mahesh5444
0

Explanation:

(a) The Ray diagram to show the formation of image of an object which is placed between the infinity and optical center of a concave lens is as follows:

The image will be obtained in between the optical centre and focus. The nature of the image formed will be virtual, erect and diminished in the size

(b) Given: Focal length of concave lens, f = -15 cm

Image distance = -10 cm

Applying the lens formula:

Object distance, u = -30 cm

(ii) Magnification is given by the ratio of size of the image to the size of the object and can be written as follows:

(iii)Since the magnification is positive and is less than 1, so the image formed will be erect and diminished in size

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