When an object is placed at 10cm infront of a concave mirror, its real image is formed at 40cm in front of mirror. What is the focal length of the mirror?
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Draw rhombus with one side of length 4.4cm angle of measure 60° Draw its diagonals measue the angles between the diagonals
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Answer:
magnification given is 4 times
it means (height of image/height of object) =(-v/u) =4
u=(-v) /4
now using the mirror formula
also here f=(-40) (focal length of concave mirror is negative)
1/f=1/v +1/u
1/(-40)=1/v + (-4)/v
1/(-40)= (-3)/v
v=3*40=120
u= (-120/4)=(-30)
u= (-30)cm
hence object should be 30 cm away from the pole
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