when an object is placed at 5 metres in front of a convex mirror of radius of curvature 6 metres then calculate the image distance and also write the properties of image ?
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Answer:
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Step-by-step explanation:
Given;
u =-5
r=6
therefore f =3
1/v= 1/f -1/u
v= uf/u-f
= -15/-8
=1.875
therefore the images virtual end erect
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