when an object is placed at a distace of 60 cm from a convex mirror, the magnification produced is 1/2. where should the object be placed to get a magnification of 1/3?
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Explanation:
they said that -v/u = 1/2 i.e, v = -u/2 = -30
put the value in mirror formula, 1/f = 1/v +1/u
you will get f here for the next -v/u =1/3 i.e, v= -u/3
put the obtained value of f and find u
solve to get the answer hope it helps............
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