Question

When an object is placed at a distance of 30 cm from a concave mirror of radius curvature 30 cm. What is the magnification of the image and why?

Answer 1

Answer:

Magnification of image = - 1

Explanation:

u = - 30 cm

R = - 30 cm

f = R/2 = - 30/2 = - 15 cm

Mirror formulae: 1 /v + 1 /u = 1 /f

1 /v = - 1 /15 + 1 /30

      = - 1 /30

v = - 30 cm

Magnification of image: m = - v /u

m = 30 /- 30

   = - 1

The image is real, inverted and is same size as that of the object.