Question

When an object is placed at a distance of 30 cm from a concave lens of focal length
I. erect
II. virtual
III.diminished

Answer 1

Answer:

Concave lens produce a virtual erect diminished image

By using len's formula, By consention μ=30 & F=−30

1/μ + 1/v = 1/f

⇒ 1/30 + 1/v = -1/30

⇒ 1/v= -1/30-1/30=1/v=-1/15

= 1/v = -0.066

So image is erect, virtual, 15cm from the lens (between lens & object).

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