when an object is placed at a distance of 40 cm from a concave spherical mirror the magnification produced is 1 by 2 where should the object be placed to get a magnification of 1 by 3
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u=40 cm
m=1/2=-v/u
1/2=-v/40
v=-20 cm
For getting mangnification 1/3,then
1/3=-20/U
U=-60 cm
ankit722:
i think its wrong
Answered by
11
m=-v/u
1/2=-v/40
v=20
and using mirror formula we can find the focal length of the mirror
in case two the v and u changes so we can get a different m but the f remains same as we r using the same mirror so let f be x
m=v/u
v=mu
substitute v=mu in the mirror formula and the f value and u will get the u value
i can only show u the path its u who have to walk on it
i hope u will be able to solve it
tq
1/2=-v/40
v=20
and using mirror formula we can find the focal length of the mirror
in case two the v and u changes so we can get a different m but the f remains same as we r using the same mirror so let f be x
m=v/u
v=mu
substitute v=mu in the mirror formula and the f value and u will get the u value
i can only show u the path its u who have to walk on it
i hope u will be able to solve it
tq
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