Physics, asked by Laur4098, 1 year ago

When an object is placed at a distance of 40cm from a concave mirror the magnification produced is 1/2. Where should the objects be placed to get a magnification of 1/3

Answers

Answered by jyashaswylenka
14

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Here is your ans

U1=-40, m1=1/2, 1/2=-(-v1)/-40 =-v1=20=v1=20 , now using mirror formula 1/f=1/v+1/u, 1/f1 =1/-20+1/40, 1/f1=+2/40 -1/40, 1/f1=-1/40,f1=-40,

m2=1/3, 1/3=-v2/u2, -v2=-u2/3, using mirror formula , 1/f2=1/v2+1/u2, f1=f2, 1/-40=-3/u2+1/u2, 1/-40=-3/u2+1/u2, 1/-40=-2/u2 , u2=-80 , the object be placed at a distance 80cm from the front side

Hope it helps.....

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