Physics, asked by akajay24, 1 year ago

when an object is placed at a distance of 50 cm from a concave spherical mirror the magnification produced is -1 by 2 where should the object be placed to get a magnification of minus 1 by 5​


Anonymous: is it - 5 cm

Answers

Answered by ksburdak
79

Magnification=-v/u

-1/2=-v/-50

v=-25cm

By using mirror formula we can calculate focal length

f=-50/3cm

Magnification=-v/u

-1/5=-v/u

u=5v

1/f=1/v+1/u

-3/50=1/5v+1/v

v=-20cm

u=5v

=5×(-20)

=-100cm

Please mark it brainliest


Anonymous: Is v - 10 or - 20
ksburdak: -10
Anonymous: Did u take lcm
ksburdak: Yes
Anonymous: I m getting - 20
ksburdak: U r right
ksburdak: Now it is correct
Anonymous: Yuppp
ksburdak: Please check the upper answer
Anonymous: Actually i r right I think because the focal length is same for all cases but the image distance varies depending on the object distance
Answered by Ankitajha212
5

Answer: Object should be placed at 100 cm

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