when an object is placed at a distance of 50 cm from its concave spherical mirror the magnification produced is -1/2 where should the object be placed to get a magnification of -1/5
Answers
Answered by
120
Hello
here is your answer
Here,
given,
m = -1/2 (means the images is real)
u = - 50 cm.
We know,
From magnification formula
m = -v/u
=> -1/2 = -v / -50
=> v = -50/2cm
=>v = -25 cm
Also,
According to the mirror formula,
=> 1/f = 1/v -(-1/u)
=> 1/f = -1/25 - 1/50
=> 1/f = (-2-1)/50
=> 1/f = -3/50 => f = -50/3 cm
So, the focal length of mirror is 60 cm.
Now, we are given that m = -1/5
m = -v/u
=> -1/5 = -v/u => v = u/5
According to mirror formula,
1/f = 1/u + 1/v
=> -3/50 = 1/u + 5/u
=> -3/50 = 6/u
Therefore, u = -300/3 = -100 cm
Therefore, required distance of the object to produce a magnification of -1/5 is 100 cm.
Hope this helps!!!!!!!!!!
Thanks for questioning
#Be Brainly
here is your answer
Here,
given,
m = -1/2 (means the images is real)
u = - 50 cm.
We know,
From magnification formula
m = -v/u
=> -1/2 = -v / -50
=> v = -50/2cm
=>v = -25 cm
Also,
According to the mirror formula,
=> 1/f = 1/v -(-1/u)
=> 1/f = -1/25 - 1/50
=> 1/f = (-2-1)/50
=> 1/f = -3/50 => f = -50/3 cm
So, the focal length of mirror is 60 cm.
Now, we are given that m = -1/5
m = -v/u
=> -1/5 = -v/u => v = u/5
According to mirror formula,
1/f = 1/u + 1/v
=> -3/50 = 1/u + 5/u
=> -3/50 = 6/u
Therefore, u = -300/3 = -100 cm
Therefore, required distance of the object to produce a magnification of -1/5 is 100 cm.
Hope this helps!!!!!!!!!!
Thanks for questioning
#Be Brainly
Answered by
27
Answer :--- Object should be placed at 100 cm.
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