Question

When an object is placed at a distance of 60 cm from a convex spherical mirror, the magnification produced is 1/2 where should the object be placed to get a magnification of 1/3​

Answer 1

Answer:

u=−60cm

u−v=21⇒−60−v=21

⇒v=30cm

⇒v1+u1=f1⇒f1=301+−601⇒f1=602−1=601

⇒f=60cm

Now magnification=31

u−v=31⇒v=3−u∴v1+u