When an object is placed at a distance of 60 cm from a convex mirror, the magnification produced is 1/2. Where should the object be placed to get the magnification equal to 1/3. i need the answer for my test tomorrow so please help me :)
Answers
Answered by
0
Answer:
place mark me as BRAINLIEST
Answered by
2
Answer:
Step-by-step explanation:
u=−60cm
u
−v
=
2
1
⇒
−60
−v
=
2
1
⇒v=30cm
⇒
v
1
+
u
1
=
f
1
⇒
f
1
=
30
1
+
−60
1
⇒
f
1
=
60
2−1
=
60
1
⇒f=60cm
Now magnification=
3
1
u
−v
=
3
1
⇒v=
3
−u
∴
v
1
+
u
1
=
f
1
⇒
3
−u
1
+
u
1
=
f
1
⇒
u
−3
+
u
1
=
60
1
⇒
u
−2
=
60
1
⇒u=−120cm
∴ Object should be placed at 120cm.
Similar questions