when an object is placed beyond the centre of curvature of a concave mirror show the diagram
Answers
If the object is represented by an arrow, then it is common practice to pick the two extreme positions (the top and the bottom of the arrow) as starting points for the incident and reflected rays. Ray construction will result in the determination of the image locations for these two extreme positions on the object. The complete image is merely an arrow connecting these two image locations. This task is further simplified if the object is positioned as an arrow standing upon the principal axis of the mirror. If this is the case, then the image will be standing upon the principal axis of the mirror (and either inverted or upright).
Of all the rays which emanate from the top of the object arrow and are incident to the mirror, there are two rays whose behavior at the mirror surface can be easily predicted. These are the two incident rays which are used in the ray construction. One of the rays moves parallel to the principal axis and reflects through the focal point. The second ray passes through the focal point on the way to the mirror and reflects parallel to the principal axis. All concave and convex mirror ray diagrams can be constructed from knowledge of the behavior of these two rays.
Answer:
Hii user ....
Good evening....
Here is your answer.....
Look at this picture ...
Ray AL parellel to the principal exis gets reflected along LF . Ray ANC , passing through the centre of curvature , gets reflected back along NCA.
These two rays intersect at A the image formed is A'B' is, therefore , an inverted , diminished image formed between F(focus) and C(center of curvature) of the mirror it is real image as the two reflected rays , LF and NCA , actually meet at the point A.
Hope this helps you......✍️
Radhe radhe ✍️
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Explanation:
