Question

When an object made of material P is kept immersed in the blue coloured solution Q. then a chemical change
takes place to form a green coloured solution R and a brown layer of substance S is deposited on the object
is used for making nails and S is used for making electric wires.
a. Identify the material P and S?
b. Name the solution Q and R.
c. Write a balanced chemical equation for the above reaction.

PLEASE TELL THE ANSWER....
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Answer 1

Answer:

P- iron

Q- copper sulphate solution

R- iron sulphate

S- copper

Fe + CoSo4 -----> FeSo4 + Cu

Answer 2

a. P- a metallic object possibly made from iron. S-rust possibly cooper sulphate depositions ensuring a successful reaction.

b. Q- blue vitriol or a solution of copper sulphate. R- green vitriol or a solution of ferrous sulphate. This reaction is a classical case of displacement or replacement and can be prevented by protection from moisture or application of appropriate external coatings.

c. The reaction is as follows:

$Fe (iron) + CuSO_{4}$ $(blue$ $vitriol)$⇒$FeSO_{4}( green$ $vitriol)$$+ Cu$$(copper$ $depostions)$