when an object of 1 cm is kept at a distance 4 cm from a concave mirror it's erect image of height 1.5 cm is formed at a distance of 6cm behind the mirror find the focal length of mirror
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Lets recall formula 1/u + 1/v = 1/f
As per cartesian sign convention
u = - 4
v = 6
f = -ve
Plug -1/4 + 1/6 = -1/f
- 1/12 = -1/f
==> f = 12 cm
Lets recall formula 1/u + 1/v = 1/f
As per cartesian sign convention
u = - 4
v = 6
f = -ve
Plug -1/4 + 1/6 = -1/f
- 1/12 = -1/f
==> f = 12 cm
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