Question

When an object of height 1 cm is kept at a distance 4 cm from a concave mirror, its erect image of height 1.5 cm is formed at a distance 6 cm behind the mirror. Find the focal length of mirror.​

Answer 1

Answer:

Given, u=−4cm,v=6cm,f=?

We know

f

1

=

v

1

+

u

1

=

6

1

−

4

1

=

12

2−3

f=−12cm

Explanation:

ANSWER IS

F=−12cm

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Answer 2

Answer:

${ \green{ \bf{ ✓Verified \: Answer}}}$

GIVEN

u= -4 cm

v= 6 cm

height of the object= 1 cm

height of the image = 1.5 cm

To Find

focal length (f)

Solution

● Mirror Formula

$\bold {\frac{1}{v} + \frac{1}{u} = \frac{1}{f} }$

$\to\frac{1}{f} = \frac{1}{6} - \frac{1}{4}$

$\to\frac{1}{f} = \: \frac{2 - 3}{12}$

$\to \frac{1}{f} = \frac{ - 1}{12}$

$\to \bold {\: f = - 12 \: cm}$

☄therefore focal lenght is -12 cm