when an object of height 1 cm is kept at a distance of 4 cm from a concave mirror it's erect image of height 1.5 cm is formed at a distance of 6 m in the mirror find the focal length of mirror
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1/v + 1/u = 1/f
1/ 6 + 1/-4 = 1/f. ( we apply minus because image produce backward
-2+3 / -12 = 1/f
1/-12= 1/f
f=-12
hope this is right thanks
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