Question

When an object of mass 10 kg is lifted through 3 metres by the application of a force tha work done by the applied force is​

Answer 1

Mass of the object given (m) = 10 kg.

⭐ Height acquired by the object (h) = 3 m.

⭐ We know, acceleration due to gravity (g)

= 9.8 m/s².

⭐ Therefore, work done by the applied force

= mgh

= (10×3×9.8) Joule

= 294 Joule {Ans.}

Answer 2

Answer:

$\maltese\underline{\textsf{\textbf{AnsWer :}}}\:\maltese✠$

✏ We're given that, mass = 10kg height = 3m acceleration due to gravity = 10m/s²

✏We need to find the gravitational potential energy

✏ Potential energy = mgh

✏ where m = mass

✏ g = acceleration due to gravity

✏ h = maximum height

$\tiny\dag\pink{\underline{\tt \gray{ PE = mgh :}}}$

$\begin{gathered}\footnotesize \longrightarrow\:\sf PE = 10\times 3 \times 10 \\ \end{gathered}$

$\begin{gathered}\footnotesize \longrightarrow\:\sf Potential\: Energy = 300\:Joules ) \\ \end{gathered}$

$\footnotesize \longrightarrow\: \underline{ \boxed{\sf Potential Energy= 300 \: J}}$