When an object of size 7 cm, is placed in front of a convex lens of distance 14 cm at point 2F1
a) What is the image distance?
b) What is the size of the image?
c) Find the magnification of the lens.
d) What is the nature of the image?
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Answer:
1) + 7 cm
2) 14cm
3) +1/2
4) real and inverted
Explanation:
as we know the lens formula
1/f=1/v-1/u
object is placed at focus so it focal length is equal to object distance
apply the formula and get the value of image distance
we know that image size / object size is equal to-v/u
magnifucation is equal to image height upon object height
correct me if i am wrong
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