Question

When an observer at a distance of 12 m from a tree looks at the top of the tree, the angle of elevation is 60°. What is the height of the tree?
(√3=1.73)

Answer 1

hi no idea what about the baby weight so don't fuc

Answer 2

Now,

tan60°= AB/ BC

√3 = AB/ 12

AB = 12√3

AB = 12× 1.73

AB = 20.76

AB = 20.8(Approx)

Hope it helps u ......