Question

when and were wil
A stone is drop from a top of torer 100m height
the same instant
another
is thrown
vertically upwords from the base of toner
with velocity of 25ms-1 mol
the stones meet (g = 10 ms-2)
​

Answer 1

Answer:

Let the stones meet at point A after time t.

For upper stone :

u =0

×=0+21

gt 2

x=21×10×t

⟹x=5t

2

............(1)

For lower stone :

u=25 m/s

100−x=ut−

2

1

gt

2

100−x=(25)t−

2

1

×10×t

2

⟹100−x=25t−5t

2

............(2)

Adding (1) and (2), we get

25t=100

⟹t=4 s

From (1),

x=5×4

2

⟹x=80 m

Hence the stone meet at a height of 20 m above the ground after 4 seconds.