Question

When any element is placed in .5 weber/meter² magnetic field than calculate the Zeeman shift of spectral line ? wavelength λ = 5000 A⁰

Answer 1

Given that,

Magnetic field = 5 weber/m²

Wavelength $\lambda= 5000\ \AA$

We need to calculate the Zeeman shift of spectral line

Using formula of Zeeman shift

$\Delta\lambda=\dfrac{\lambda^2eB}{4\pi mc}$

Where, B = magnetic field

$\lambda$ = wavelength

m = mass of electron

c = speed of light

Put the value into the formula

$\Delta\lambda=\dfrac{(5000\times10^{-10})^2\times1.6\times10^{-19}\times}{4\pi\times9.1\times10^{-31}\times3\times10^{8}}$

$\Delta\lambda=5.82\times10^{-11}\ m$

Hence, The Zeeman shift of spectral line is $5.82\times10^{-11}\ m$