when any natural number is divided by 10, what is the sum of all possible remainder
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When any number is divided by 10 the remainder can be any of the number from 0 to 9
so the sum of all possible remainders is
0+1+2+3+4+5+6+7+8+9+45
so the sum of all possible remainders is
0+1+2+3+4+5+6+7+8+9+45
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it should be zero because if n is natural number and is dovisible by 10 then will always 0
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