When any natural number is divided by 10 what is the sum of all possible remainders
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Answered by
4
HEY DEAR BRAINLY USER
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UR ANSWER IS =
first read the Divisibility rule of 10 so its said that Any number with unit digit 0 is divisible by 10..
So, now let's check the remainders
the remainders are 1,2,3,4,5,6,7,8,9 because only unit digit 0 can be divisible..
So, their sum =1+2+3+4+5+6+7+8+9=45
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Anonymous:
sorry i cant bcoz may be uh block me or ur band
Answered by
2
Answer:
45
Step-by-step explanation:
>>>>so the sum of all possible remainders is
>>>> 0+ 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9
= 45
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