When aqueous magnesium chloride reacts with liquid bromine
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Answer:
MgCl2(aq) + Br2(l) - MgBr2(in aq solution)+ Cl2(gas)
as while combining magnisium and chlorine you will see that -
Mg Cl
2 × 1=MgCl2 +Br2 (These are the reactants on the left hand side).....(1)
now, br is more reactive than cl which will results in displacing of cl by br
Mg Br
2 × 1 =MgBr2 +Cl2(products on right hand side).......(2), Now by combining (1)&(2), we get-
=MgCl2(aq) + Br2(l) - MgBr2(aq) + Cl2(g)
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