Question

When aqueous sodium hydroxide is added dropwise until in excess to an unknown salt solution, a green precipitate is formed and is insoluble in excess aqueous sodium hydroxide. The precipitate turns brown slowly.Which of the following is the unknown salt?​

Answer 1

Answer:

Zinc Sulphate

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Answer 2

Answer:

Zinc Sulphate is the unknown Salt.

Explanation:

The molecular formula for sodium hydroxide is $NaOH$ and zinc sulphate is $ZnSO_4$.

The reaction of sodium hydroxide with zinc sulphate is:

$ZnSO_4+2NaOH\rightarrow Zn(OH)_2+Na_2SO_4$

When sodium hydroxide reacts with zinc sulphate a precipitate of $(Zn(OH)_2)$  is formed. The zinc hydroxide precipitate is white in color.

Now, the reaction of white precipitate of zinc hydroxide with sodium hydroxide is:

$Zn(OH)_2+NaOH \rightarrow Na_2ZnO_2+2H_2O$

Thus, when white precipitate of zinc hydroxide reacts with sodium hydroxide a soluble salt of $Na_2ZnO_2$  is formed.

Thus, when sodium hydroxide is added dropwise until in excess to a solution of zinc sulphate it is observed that white precipitate is formed which is soluble in excess of sodium hydroxide.

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