Question

when athlete completes a round of a circular track of diameter 200m in 20 seconds calculate-(i) the distance travelled by athelete.(ii) the magnitude of the displacement of the athlete at the end of 1 minute 10 second​

Answer 1

Given,

Diameter of the circular path (d) = 200 m

Radius (r) = d/2

= (200/2) m

= 100 m

pi = 3.14

Circumference of the Circle = 2*pi*r

= 2*3.14*100 m

= 628 m

i. This means to complete one round, one has to travel 628 m.

Time taken to cover 628 m = 20 seconds

Distance Covered in 1 second = 628/20 m

= 31.4 m

Distance Covered in 70 seconds = (31.4*70) m

= 2198 m

ii. Displacement at the end of 70 seconds = (628*3) = 1884 m

= (2198-1884) m

= 314 m

The Distance Covered in 20 seconds is 628 m and Displacement after 70 seconds is 314 m.

I hope this helps.