Question

when atmospheric air is heated at constant pressure its

Answer 1

Density gets decreased and moves up.

Answer 2

Consider when atmospheric air is heated up at constant pressure its density gets decreased and moves up.

According to ideal gas equation, we get ,

                                               PV = nRT

Where,

P = “Pressure”

V = “Volume”

R = “Gas constant”

T = “Temperature”

            $V\quad =\quad \frac { nR }{ P } \quad \times \quad T$

Since, Volume is,

            $Volume\quad =\quad \frac { Mass }{ Density }\quad =\quad \frac { m }{ \rho }$

            $\frac { m }{ \rho } \quad =\quad \frac { nR }{ P } \quad \times \quad T$

Where, m, R, n, P are considered as constant.

            $\frac { 1 }{ \rho } \quad \propto \quad T$

Since, density is inversely proportional to temperature. “Increase in temperature” will decrease the density.