when ax³+bx²+cx-4 is divided by x+2 the remainder is double that obtained when the expression is divided by x+1. show that c can have any value and find b in terms of a
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Answer: b=3a-2
'c' can have any value
Step-by-step explanation:
remainder of given expression when divided by x+1 is (b-c-a-4)
remainder of given expression when divided by x+2 is (4b-2c-8a-4)
given 2(b-c-a-4)=4b-2c-8a-4
2b-2c-2a-8=4b-2c-8a-4
b=3a-2
'c' can have any value
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