When B2H6 reacts with excess ammonia at room temperature select correct about product
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3
Answer:
B3N3H6
Explanation:
B2H6+2NH3=B2H6.2NH3
3B2H6.2NH3= 2B3N3H6 + 12H2
(inorganic benzene)
Answered by
0
B2 H6 reacts acts at low temperature with ammonia to form B2H6.2NH3
Or it at reacts at high temperature s with ammonia to form( BN)x boron nitride
I hope this helps ( ╹▽╹ )
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