Question

.When Barium chloride reacts with aluminium sulphate, white precipitate of Barium sulphate

and aluminium chloride are formed. Which of the following is the correct representation in

equations?

a) BaCl2 + Al2(SO4)3

BaSO4 + AlCl3

b) 3BaCl2 + Al2(SO4)3

3BaSO4 + 2AlCl3

c) 3BaCl2(aq)+ Al2(SO4)3(aq)

3BaSO4(aq) + 2AlCl3(aq)

d) BaCl2(aq) + Al2(SO4)3(aq)

BaSO4(aq) + AlCl3(aq)

3​

Answer 1

Al2(SO4)3 + 3BaCl2→ 2AlCl3 + 3BaSO4

Answer 2

Answer:

a) BaCI2+Al2(SO4) 3-BaSO4+AlC13

Explanation:

so overall reaction isc:

BaC12+A12(SO4) 3-AlC13+BaSO4

now,balancing the equation as the number of elements as they are not equal on both sides.