Chemistry, asked by balpreetkaur3847, 1 year ago

When benzamide is treated with br2 in presence of aqueous koh then the end product formed is

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Answered by durgasampath26
2

2Br+2KOH------>2Br(OH)+2K


Here the reaction is displacement reaction because the potassium (K)is more reactive than bromine (Br).


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