when body moves at an angle of 180 degree how much work in done
Answers
Answer:
Work done: W = F*S*cos(theta)
Work done: W = F*S*cos(theta)W is positive when 0° < theta < 90°
Work done: W = F*S*cos(theta)W is positive when 0° < theta < 90°W = 0 [when theta= 90°]
Work done: W = F*S*cos(theta)W is positive when 0° < theta < 90°W = 0 [when theta= 90°]W is negative when 90° < theta < 180° .
Work done: W = F*S*cos(theta)W is positive when 0° < theta < 90°W = 0 [when theta= 90°]W is negative when 90° < theta < 180° .Negative W means that the work is done in the opposite direction of the displacement, but doesn't mean it is the least because it is negative but it just means that it is in the opposite direction.
Work done: W = F*S*cos(theta)W is positive when 0° < theta < 90°W = 0 [when theta= 90°]W is negative when 90° < theta < 180° .Negative W means that the work is done in the opposite direction of the displacement, but doesn't mean it is the least because it is negative but it just means that it is in the opposite direction.This is a common misconception here. If you reverse the sign convention of the directions of motion and force, and then observe the work done, you'll find that the positive work done, which you got in the first case, will be negative in the reversed case. It's a matter of the convention you take. But the minimum in any case is no work done at all.
Work done: W = F*S*cos(theta)W is positive when 0° < theta < 90°W = 0 [when theta= 90°]W is negative when 90° < theta < 180° .Negative W means that the work is done in the opposite direction of the displacement, but doesn't mean it is the least because it is negative but it just means that it is in the opposite direction.This is a common misconception here. If you reverse the sign convention of the directions of motion and force, and then observe the work done, you'll find that the positive work done, which you got in the first case, will be negative in the reversed case. It's a matter of the convention you take. But the minimum in any case is no work done at all.So the minimum work done will be 0 (i.e; when theta = 90°).
Work done: W = F*S*cos(theta)W is positive when 0° < theta < 90°W = 0 [when theta= 90°]W is negative when 90° < theta < 180° .Negative W means that the work is done in the opposite direction of the displacement, but doesn't mean it is the least because it is negative but it just means that it is in the opposite direction.This is a common misconception here. If you reverse the sign convention of the directions of motion and force, and then observe the work done, you'll find that the positive work done, which you got in the first case, will be negative in the reversed case. It's a matter of the convention you take. But the minimum in any case is no work done at all.So the minimum work done will be 0 (i.e; when theta = 90°).Hope you find it useful.