Chemistry, asked by torral1508, 10 months ago

When Br₂ is treated with aqueous solutions of NaF, NaCl
and NaI separately
(a) F₂, Cl₂ and Iv are liberated
(b) only F₂ and Cl₂ are liberated
(c) only I₂ is liberated
(d) only Cl₂ is liberated

Answers

Answered by trishabansal1207
1

Answer:

b

Explanation:

i guess its the answer

hope it helps

Answered by kingofself
1

When Br₂ is treated with aqueous solutions of NaF, NaCl  and NaI separated only I₂ is liberated.

Explanation:

  • Bromine present in the group 17 which is a halogen.
  • Within this group the elements placed above are displaced below in the redox reaction.

Redox reaction

  • In a chemical reaction, the atoms oxidation state were changed. Both reduction and oxidation reaction taken place.

Reaction of bromine

  • When Bromine reacts with aqueous solution of NaCl, NaF, NaI are separated, then iodine is liberated.
  • Due to less reactivity of bromine than chlorine and iodine. Hence it is displaced.
  • When bromine treated with NaI, iodine is displaced due to the reactivity of iodine is more.  

                      2NaI + Br{2}2NaBr + I{2}

To learn more;

  1. https://brainly.in/question/15419647
  2. https://brainly.in/question/1631623

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