when brakes are applied the speed of train decreases from 96kmh to 48kmh in 800m how much farther will the train move before coming to rest find the time taken by train to stop after application of brakes
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From 3rd equation of motion v^2-u^2=2as from first given v=96,u=48,s=800m a=-3.84 km/h^2 from same equation now take v as 48 , u as 0 and a as got now s= 300m to stop. Or can be get by same process with changing unit of velocity to m/s will get approx 266 m.
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