when brakes are applied to a car moving with a velocity of 54 km^-1 it comes to rest within 2 metre. calculate the frictional resistance of a car if its mass is 150 kg.
please solve with process and steps
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With the given data, one can easily calculate the value of retardation of the car by using the equation of motion:
v^2 - u^2 = 2as
where
'v' is the final velocity of the car which is 0 (because the car comes to a halt after applying the brakes)
'u' is the initial velocity of the car which is
10 m/s
'a' is the retardation which is to be determined
's' is the distance the car treads after applying the brakes and coming to a halt, which is 20 m
Thus, the retardation comes out to be
2.5 m/s^2
Now, we know that
Force = Mass x Acceleration
Assuming the mass of the car to be M kg, the stopping force comes out to be 2.5M Newtons
Now if this force were to stop the same car travelling at 30 m/s, it would produce the same retardation as it did earlier, because the mass of the car is unchanged.
Now, u = 30 m/s instead of 10 m/s
Using the same equation
v^2 - u^2 = 2as
The stopping distance 's' comes out to be
180 m
v^2 - u^2 = 2as
where
'v' is the final velocity of the car which is 0 (because the car comes to a halt after applying the brakes)
'u' is the initial velocity of the car which is
10 m/s
'a' is the retardation which is to be determined
's' is the distance the car treads after applying the brakes and coming to a halt, which is 20 m
Thus, the retardation comes out to be
2.5 m/s^2
Now, we know that
Force = Mass x Acceleration
Assuming the mass of the car to be M kg, the stopping force comes out to be 2.5M Newtons
Now if this force were to stop the same car travelling at 30 m/s, it would produce the same retardation as it did earlier, because the mass of the car is unchanged.
Now, u = 30 m/s instead of 10 m/s
Using the same equation
v^2 - u^2 = 2as
The stopping distance 's' comes out to be
180 m
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