Question

When brakes are applied to a train running on a straight line, it stops after covering 200 m distance. What would be the retardation the produced in the train ?​

Answer 1

Answer:

The retardation produced in the tarin is - 0.25m/$s^{2}$

Explanation:

Given :-

v = 0m/s               s = 200m

u = 36km/hr

u = 36×5/18

u  = 10m/s

Using 3rd equation of motion,

$v^{2}-u^{2} =2as$

$0^{2}-u^{2}=2as$

a = $\frac{-u^{2} }{2s}$

a = - 10×10/2×200

a = -1/4

a = -0.25m/$s^{2}$