when break is applied, the speed of cycle is reduced from 2 m/sec to 1 m/sec. Determine the work done during this interval ? given mass of cycle along with rider = 10 kg
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Answer:
-15
Explanation:
Work done is equal to change in kinetic energy=(final-initial)Kinetic energy
Kinetic energy=(1/2)mv^2
The work done by retardation will come negative
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