when breaks are applied to a bus the retardation produced is 25cm/s^2 and the bus takes 20s to stop.calculate the initial velocity
Answers
Answered by
4
Retardation (-a) = - 25 cm/s2
Time taken to get stopped (tav)=20 second
As the bus starts from rest,
∴ final velocity (v)= 0
Initial velocity (u)= ?
Distance(s) = ?
First we will calculate initial velocity of the bus.
We know
a = (v - u ) / t
- 25 = (0 - u )/ 20
-25 = - u /20
u = 25x 20
∴ u = 500 cm/s
u = (500/100) m/ s
u= 5 m/s
∴ Initial velocity (u) = 5m/s
Time taken to get stopped (tav)=20 second
As the bus starts from rest,
∴ final velocity (v)= 0
Initial velocity (u)= ?
Distance(s) = ?
First we will calculate initial velocity of the bus.
We know
a = (v - u ) / t
- 25 = (0 - u )/ 20
-25 = - u /20
u = 25x 20
∴ u = 500 cm/s
u = (500/100) m/ s
u= 5 m/s
∴ Initial velocity (u) = 5m/s
Similar questions