When bucket is filled 3/8 of its capacity with water,its weight is 10kg.If it is filled 3/5 of its capacity with the water its weight is 14.5 kg.How much will its weight be when it is filled to the full capacity with water?
Answers
Answer:
22.5 kg
Step-by-step explanation:
Let the weight of empty bucket be x kg . Let the weight of water the empty bucket can hold to it's full capacity be y kg.
x + 3/8y = 10 --- [1]
x + 3/5y = 14.5 ---- [2]
Subtract [1] from [2]
3/5y - 3/8y = 14.5 - 10
(24 - 15/40)y= 4.5
9y/40 = 4.5
=> y = 4.5 * 40/9 = 20 kg.
Substituting value of y in [1]
x + 3/8 * 20 = 10
=> x = 10 - 7.5 = 2.5 kg
Thus total weight when filled with water = x + y = 2.5 + 20 = 22.5 kg
Answer:
The weight of the bucket fully filled with water is 22.5 kg.
Step-by-step explanation:
Let x denotes capacity of bucket and y denotes its weight
x+3/8y = 10 ...(1)
x+3/5y = 14.5 ...(2)
3/8y+3/5y = 24y+ 15/40y ...(3)
substituting EQ.3 in EQ. 2 and 1
x+3/8y =10 ...from (1)
x + 24y =10... (4)
x+3/5y = 14.5 ...from(2)
x+ 15/40y = 14.5...(5)
Subtracting eq. (4) from eq. (5)
(x+24y=10) + ( x+15/40y = 14.5)
y= 22.5 kg
y = weight of a bucket
hence,
The weight of the bucket fully filled with water is 22.5 kg.