Question

When burnt in air, 14.0g mixture of carbon and sulphur
gives a mixture of Co, and So, in the volume ratio of 2 : 1,
volumes being measured at the same conditions of
temperature and pressure. Moles of carbon in the mixture
is:
(a) 0.25
(b) 0.40
(c) 0.5
(d) 0.75​

Answer 1

Answer:

I think the ans is b option

Answer 2

The volume ratio produced = 2:1

That means double the moles of carbon dioxide is produced

Let, mass of carbon = x g

Mass of S = (14−x) g

Moles of carbon=  

12

x

​  

 

Moles of S =  

32

14−4

​  

 

and we have

2×moles of carbon=moles of S

2×  

12

x

​  

=  

32

14−x

​  

 

On soving, we get x = 6 g

∴ Moles of carbon =  

12

6

​  

=0.5