When carbon compound having formula c6h4o is oxidised with alkaline kmno4 a product x is obtained. What is x?
Answers
Substance X is Hexanoic acid
Not sure
Generally amines go through a number of steps to undergo oxidation, depending upon the oxidising agent and/or other parameters:

Here are a nuber of possible ways in which an amine can undergo oxidation with KMnO4.
Primary amine:
RCH2 NH2 ———→ RCH = NH (aldimine) ———→ RCHO (aldehyde) + NH3
R2 CHNH2 ———→ R2C = NH (ketimine)———→ R2CO (ketone) + NH3
R3C-NH2 ———-> R3C-NO2
Tertiary alkylamines, with KMnO4, are generally oxidised to nitro compounds (when the -NH2 group is attached to a tertiary carbon).
In both of the first cases, KMnO4 is the oxidising agent and is used in the first step. H2O is used as the second step.
Secondary amine:
R2NH ——→ R2N-NR2 (Tetra-alkyl hydrazine), with KMnO4.
With Caro’s acid (H2SO5):
R2NH ——→ R2NOH (Hydroxylamine)
Tertiary amine:
Mostly they won’t be oxidised by KMnO4 but by Peroxymonosulfuric acid, (H2SO5) or Caro’s acid, to form amine oxides