Science, asked by rutujaudaysathe1, 7 months ago

when certain conduct cell filled with 0.20mol dm-3 aqueous KCI soln it conductivity was 2.78*10-3Scm-1 and had a resistance 82.5ohm at 300k calculate the cell constant of the cell

Answers

Answered by MrSudipTO
1

The specific conductance (κ) is the product of cell constant (  l/a ) and reciprocal of resistance (1/R  ).

cell constant (  l/a )=

​κ×R=2.78×10 ^ −3  ohm ^ −1  cm ^ −1  ×82.5ohm=0.2281cm  ^−1  = ANS

( ********** please calculate using calculator*************)

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