When certain metal was inradiated.with Light of frequency 3.2×10 power 16 Hz the photoelectrons emitted had twice the kinetic energy as did photoelectrons emitted when the same metal was irradiated with light of frequency 2×10 power 16 Hz calculate threshold frequency
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Explanation:
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Answer:
Applying photoelectric equation,
KE=hv−hv
0
or (v−v
0
)=
h
KE
Given, KE
2
=2KE
1
v
2
−v
0
=
h
KE
2
...(i)
and v
1
−v
0
=
h
KE
1
...(ii)
Dividing equation (i) by equation (ii),
v
1
−v
0
v
2
−v
0
=
KE
1
KE
2
=
KE
1
2KE
1
=2
or v
2
−v
0
=2v
1
−2v
0
or v
0
=2v
1
−v
2
=2(2.0×10
16
)−(3.2×10
16
)
=8.0×10
15
Hz.
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