When CH3 CH2 CHCl2 is treated with NaNH2, the product formed is : -
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CH2=CH-CH2-CHCl2 is on the treatment with C2H5ONa in C2H5OH as shown in the figure.
CH3 - C ≡ CH
So in the reaction is continued for further CH2=CH-C=-CH (read the last =- as a triple/acetylene bond) can be obtained.
3-chlorobutanol acid with a magnitude and the number of bonds will have the negative charge. The acid will increase the acidity which is to be effected to the closer of an acidic group.
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