Question

When Cl₂ gas reacts with hot and concentrated sodium
hydroxide solution, the oxidation number of chlorine changes
from :
(a) zero to +1 and zero to –5
(b) zero to –1 and zero to +5
(c) zero to –1 and zero to +3
(d) zero to +1 and zero to –3

Answer 1

Answer:

option 1 is correct.

NaOH+Cl2 =NaOCl+NaClO3+H2O

Answer 2

When chlorine gas react with hot and concentrated sodium hydroxide solution then the oxidation number of Chlorine gas changes from 0 to -1 and 0 to + 5.

● The reaction that occurs in the above mentioned condition is disproportionate reaction.

● In case of a disproportionation reaction, a similar component experiences oxidation just as reduction.

● Right now, number of chlorine changes from 0 to - 1 and 0 to +5.