Question

When Cl₂ gas reacts with hot and concentrated sodium
hydroxide solution, the oxidation number of chlorine changes
from : [2012]
(a) zero to +1 and zero to –5
(b) zero to –1 and zero to +5
(c) zero to –1 and zero to +3
(d) zero to +1 and zero to –3

Answer 1

The oxidation number of chlorine changes  from  zero to –1 and zero to +5.

Option (B) is correct.

Explanation:

• The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is

• The chemical reaction:

• 3Cl2 + 6NaOH ----->  NaClO3 + 5NaCl + 3H2O

• Oxidation number of Cl is 0 in Cl2  ,−1 in NaCl and +5 in NaClO3.

• Therefore the oxidation number of chlorine changes from Zero to -1 and Zero to +5.

Hence the oxidation number of chlorine changes  from  zero to –1 and zero to +5.

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