Question

When Cl2 gas reacts with hot and concentrated sodium
hydroxide solution, the oxidation number of chlorine changes
from​

Answer 1

Answer:

Explanation:

3Cl_{2}+N_{a}OH\rightarrow 5N_{a}Cl^{-1}+N_{a}Cl^{+5}O_{3}+3H_{2}O

Option 1)

Zero to +1 and zero to -5

Incorrect

Option 2)

Zero to -1 and zero to +5

Correct

Option 3)

Zero to -1 and zero to +3

Incorrect

Option 4)

Zero to +1 and zero to -3

Incorrect

Answer 2

Answer:

The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is

3Cl₂ + 6NaOH ⟶ NaClO₃+ 5NaCl +3H₂O

Oxidation number of Cl is 0 in Cl₂ , -1 in NaCl and +5 in NaClO₃

So the oxidation number of chlorine changes from Zero to -1 and Zero to +5.

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