When concentration of a reactant is doubled, the rate of reaction becomes four times. The order of reaction is?
Answers
Answer:
As we know that, The Rate of reaction is directly proportional to the concentration of the reactant raised to its order.
=>Rate=k * [A] o
(Here k is the rate constant,
[A] is the concentration
o is the order of the reaction.)
According to the question, New rate = 2 * Old rate,
And
new concentration = 4 * old concentration.
=>k∗(4∗[A])o = 2∗k∗[A]o
=>4o = 2
ans: o = 0.5
Therefore the order is 0.5.
As we know that, The Rate of reaction is directly proportional to the concentration of the reactant raised to its order.
=>Rate=k * [A] o
(Here k is the rate constant,
[A] is the concentration
o is the order of the reaction.)
According to the question, New rate = 2 * Old rate,
And
new concentration = 4 * old concentration.
=>k∗(4∗[A])o = 2∗k∗[A]o
=>4o = 2
ans: o = 0.5
Therefore the order is 0.5